x^2+40x-3200=0

Solution for x^2+40x-3200=0 equation:

x^2+40x-3200=0

a = 1; b = 40; c = -3200;
Δ = b2-4ac
Δ = 402-4·1·(-3200)
Δ = 14400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{14400}=120$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(40)-120}{2*1}=\frac{-160}{2}
=-80
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(40)+120}{2*1}=\frac{80}{2}
=40
$